Ramosaurio's questions

Hello, I am an average user of Linux systems, and I want to get into the mess that Gentoo supposes, I have a "little problem" when installing:

I am installing it from my distribution which is Ubuntu, and this is where my problems begin, I want to partition the disk (which is good after being informed by google, I will use a default "folder" system, which is the one that comes in all the tutorials from Internet.

I enclose the image of how my partitions are distributed that Ubuntu created for me when I installed it:

Well, what happens? Well, to begin with, I have to make the partitions from partition 2 (/dev/sda2). But being logged in from my user (from what I have read) I cannot access to unmount the disk (to resize it and make my partitions) since I am "using" my personal folder that is in that partition.

Any idea how to log in as root, without having to log in with my user? Or any way to unmount the partition and resize it ?

And regarding GPT partitions, what is the difference between MBR and GPT partitions, I don't understand very well what advantages and disadvantages each one has.

Greetings and thank you.

We have the following function:

repartir [a] -> ([a],[a])

So partition should partition the main list into two lists by taking the elements like this:

repartir [1,2,3,4,5]

---> ([1,3,5],[2,4])

repartir "hola"

---> ("hl","oa")

We can only import:import Data.List

Greetings and thank you

Hi, I have the following tuple:

ordena :: Ord a => (a,a,a) -> (a,a,a)

Let's see this is not very complicated but as I do it I get a very ugly and long code.

In this case I ask to see if there is some type of recursion that I can do to order it from smallest to largest

I have the following function:

ParesImpares:: [Integer] -> ([Integer],[Integer])

I have to get even and odd numbers out of a list:

ParesImpares [3,2,4,5,7]

->([2,4],[3,5,7])

My code so far is as follows:

    paresImpares :: [Integer] -> ([Integer],[Integer])
    paresImpares [] = ([],[])
    paresImpares [x] 
    | x `mod` 2 == 0 = ([x],[])
    | otherwise = ([],[x]) 

I have defined a base case, but the truth is that I don't know how to proceed. I had in mind something like:

ParesImpares(x:xs) = ParesImpares [x]

But of course, it only evaluates the first element of the list.

Hello good I have a problem in hand try to make a code in Haskell with the following conditions:

We introduce two numbers a y bfor it to be divided a/b by type Integer, so that we have its module and its quotient

With the following restrictions only additions, subtractions and comparators can be used neither div, nor mod, nor anything can be used

//Edited from here

cocienteYResto:: Integer -> Integer -> (Integer, Integer)
cocienteYResto x y 
    | x < y = (x,?????)
    | otherwise = ((cocienteYResto (x - y) y))

well here as we see when x< yI am returning the rest, but I have no way, well rather I do not know how to get that quotient (this right now does not even observe that it is divided by 0, nor that x<yin a base case

you just have to divide things like 3/2 10/4, but nothing 3/8 .

Suggestions of all kinds are accepted, I'm starting and any help is good for me.

Greetings and thank you

I'm trying to learn the methods of LibGDX and I've started a project, it's the old Atari Lunar Landscape game.

I simply want to generate the following "scenario"

I just want to do what amounts to mountains, and of course I have the following things in mind to do it in a "random" way.

Have the following variable:

int NumeroPuntos

This variable will receive a random number between 30 and a maximum yet to be determined to see how many geometric points the map will be formed and then join these points with a ShapeRender.

But I can't think of any way to generate a "uniform" mountain, that is to say that it has the shape of a mountain and also that it has uniform parts that serve as a base (which are the ones that say x2, x5, x3...)

And the last question regarding this is, how to make more maps be generated? that is, is there any method to move the current screen so to speak and generate another one?

For example if my "Screen" has value x = 100, and value y = 30, can I draw outside the screen so that when the screen moves it is automatically generated?

Hello, I have created a small button in android, with very simple libGDX, but the problem is the following:

I have assigned a function that writes ("hola")something like this to the screen:

if(boton.sePulsa()){
   System.out.println("hola")
  }

and of course, it prints on the screen 3 times or more, "hola"and I want it to not print anything until it is pressed again. Any help pls.

//I edit the function sePulsa()is as follows:

public boolean sePulsaElBoton() {
    return Gdx.input.isTouched() && Gdx.input.getX() >= xMinima && Gdx.input.getX() <= xMaxima &&
            Gdx.input.getY() >= yMinima && Gdx.input.getY() <= yMaxima;
}

xMaxima,Xminima, Yminima ,YMaximaare of type float.

I am making a test program that consists of:

• 4 buttons, up, down, left and right.
• A spaceship, formed by a Rectangle ( Rectangle) and its respective image ( Texture).

Boton arriba,moves up

Boton abajo, it moves down.

Boton izquierdo, rotates counterclockwise on itself Boton derecho, rotates clockwise on itself

I can't find any method to make the right and left button work. Thanks in advance.

I try to put a Backgroundin the app, something very simple to learn the use of canvasandbitmaps

protected void onCreate(Bundle savedInstanceState) {

    super.onCreate(savedInstanceState);

    requestWindowFeature(Window.FEATURE_NO_TITLE);

    getWindow().setFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN, WindowManager.LayoutParams.FLAG_FULLSCREEN);

    setContentView(new Vista(this));
}

public class Vista extends View{

    public Vista(Context context ){
        super(context);
    }

    protected void onDraw(Canvas canvas){
        Paint mipincel = new Paint();
        Bitmap res = BitmapFactory.decodeResource(getResources(),R.drawable.grassbg1);
        res.

        canvas.drawBitmap(res,0,0,null);
    }
}

Well, I understand that with canvas.drawBitmap(res,0,0,null)I am placing my image at the point (0,0) from canvaswhich I have created, but of course the image does not occupy the entire screen (I suppose because of its size and others), what method or what type of I must do this scaling to get it to occupy the entire background, and of course, that it is scaled for any type of screen. All the best.

I've been browsing the APIandroid for a while trying to understand the function of BitmapFactory.

At what times am I supposed to use BitmapFactory, and why?

I don't quite understand the use of Parcelable()and Serializable().

What is the difference between Serializable()and a Parcelable()?

In which cases can I use a Parcelableand in which cases a Serializable?

How can I send a Map<String,Integer>= new HashMap<>();from one activity to another, using Intent?