Questions[lista]

I have the following function developed in Haskell, it performs an avg of 3 entered notes and depending on the condition it counts the elements of the list (using length), the first output of the tuple should be count( ) when the condition >= 4 and the second count( ) when it is < 4:

funcion1::[(String, Int,Int,Int)]->(Int,Int)
funcion1 ((nombre,nota1,nota2,nota3):xs) = ( if (nota1+nota2+nota3) `div` 3 >=4 then 1 + funcion1 xs else funcion1 xs ,
                                             if (nota1+nota2+nota3) `div` 3 <4 then 1 + funcion1 xs else funcion1 xs )

However, when entering data in the input, the tuple always returns the same values ​​for both cases (Example: When entering 3 elements with avg >= 4 and only 1 with avg < 4, the output should be (3,1) and currently it is ( 3.3).

I have searched for information on the net, regarding how to insert an element in the middle of a list in Prolog, but I have not found relevant information regarding what I want to do.

%Create_a_program_in_Prolog_that_inserts_an_element_in_the_half_of_a_list %insert_half([a,b,c,d,e,f],x,R). %R=[a,b,c,x,d,e,f].

I am new to using the Prolog program and learning its logic. Also, I'm honest, it's a university exercise and I don't know how to do it, thanks in advance

I want to do a list comprehension so that it gives me the same result with less code. what the code does is print the letters [ gatopercnj ] that is, with the first two for achievement it is ready [ 'g','a','t','o','p','e','r ','r','o','c','o','n','e'',j'',o'] is ready now stored in the variable called list_letters, I want it to store in the variable result only non-repeating words ['g','a','t:','o','p','e','r','c','n','j'] With the previous code I can execute it but now I want to perform a list comprehension to the code.

lista_palabras = ["gato","perro","conejo"]
lista_letras = [ ]
resultado = [ ]
for una_palabra in lista_palabras:
 for una_letra in una_palabra:
  lista_letras.append(una_letra)
  #quiero una letra de la var lista_letras
for letra in lista_letras: 
  #si la letra no esta en la var resultado
 if letra not in resultado:
  #se agrega la letra a la var resultado
  resultado.append(letra)
  #solo se almacenan las letras que no esten en la variable y listo
print(resultado)

Good morning, a question made me balls when I wanted to do the following I have this structure

Data = [
    {"id" : 1, "nombre" : "A", "cantidad" : 20},
    {"id" : 1, "nombre" : "A", "cantidad" : 30},
    {"id" : 2, "nombre" : "B", "cantidad" : 15},
    {"id" : 2, "nombre" : "B", "cantidad" : 10},
    {"id" : 3, "nombre" : "C", "cantidad" : 20}]

I want to get this result only from the id's without duplicate

R=[{"id" : 1}, {"id" : 2}, {"id" : 3}]either

R = [1, 2, 3]

Trying to do this problem in Python: https://leetcode.com/problems/two-sum/ ...I have the following doubt... So far the code I have is this.

class Solution:
def twoSum(self, nums, target: int):
    for i in nums:
        for j in nums:
            if i + j == target and nums.index(i) != nums.index(j):
                print (nums.index(i), nums.index(j))

Specifically, the problem is that when iterating with the for loops the list that is entered, assuming that the list has 2 equal elements, only the first element is iterated, due to the characteristics of the lists, but I need to iterate all the elements even if they are repeated . Is there any solution or am I misapproaching the problem?