All Questions

I think my question should be simple to answer, but I really don't know the answer so here goes:

I am trying to subtract the original height from a layout50 dps. Right now I do it as follows:

v.getLayoutParams().height = initialHeight -  50;
v.requestLayout();

The problem with this is that it's subtracting via the metric px, and I'd like to work withdp

I have a java application ( index.java) that if I execute it I navigate through its different JFrameor JDialogwithout problems, etc.

My doubt/question/query is: is there any method to not allow opening during the process of index.javaanother index.java? And in case of trying to reopen it (if it is open) show a message: "It is in use".

I hope I have explained myself.

Code:

public class Index extends javax.swing.JFrame {
    public Index() {
        initComponents();
        //Fondo del JFrame en color gris.
        getContentPane().setBackground(Color.gray);
        //Código para confirmar el cierre de la ventana principal.
        setDefaultCloseOperation(javax.swing.WindowConstants.DO_NOTHING_ON_CLOSE);
        addWindowListener(new java.awt.event.WindowAdapter() {
            @Override
            public void windowClosing(java.awt.event.WindowEvent evt){
                if (JOptionPane.showConfirmDialog(rootPane, "¿Desea salir de la aplicación?", "Salir de la aplicación",
                    JOptionPane.YES_NO_OPTION) == JOptionPane.YES_OPTION)
                    System.exit(0);
            }
        });

        //Situamos el JDialog en el centro de la pantalla.
        setLocationRelativeTo(null);
        //No redimensionable.
        setResizable(false);
    }

    public static void main(String args[]) {
        /* Set the Nimbus look and feel */
        //<editor-fold defaultstate="collapsed" desc=" Look and feel setting code (optional) ">
        /* If Nimbus (introduced in Java SE 6) is not available, stay with the default look and feel.
         * For details see http://download.oracle.com/javase/tutorial/uiswing/lookandfeel/plaf.html 
         */
        try {
            for (javax.swing.UIManager.LookAndFeelInfo info : javax.swing.UIManager.getInstalledLookAndFeels()) {
                if ("Nimbus".equals(info.getName())) {
                    javax.swing.UIManager.setLookAndFeel(info.getClassName());
                    break;
                }
            }
        } catch (ClassNotFoundException ex) {
            java.util.logging.Logger.getLogger(Index.class.getName()).log(java.util.logging.Level.SEVERE, null, ex);
        } catch (InstantiationException ex) {
            java.util.logging.Logger.getLogger(Index.class.getName()).log(java.util.logging.Level.SEVERE, null, ex);
        } catch (IllegalAccessException ex) {
            java.util.logging.Logger.getLogger(Index.class.getName()).log(java.util.logging.Level.SEVERE, null, ex);
        } catch (javax.swing.UnsupportedLookAndFeelException ex) {
            java.util.logging.Logger.getLogger(Index.class.getName()).log(java.util.logging.Level.SEVERE, null, ex);
        }
        //</editor-fold>
        //</editor-fold>

        /* Create and display the form */
        java.awt.EventQueue.invokeLater(new Runnable() {
            public void run() {
                new Index().setVisible(true);
            }
        });
    }
}

I would like to know what is the most efficient way to compare the contents of two arrays, to do this in the least amount of time and to use the least amount of resources.

I present this example in Python of how I do it on a daily basis. For this example, there are few elements, it takes very little time, but as we add elements, the times increase exponentially.

If you want to give an example in another welcome language, the idea is to know the logic of how to do it over the language.

Here the example:

#!/usr/bin/python
# -*- coding: utf-8 -*-

arreglo1   = [1,2,3,4,5,6]
arreglo2   = [0,2,4,6,8,10]
repetidos  = []

for x in arreglo1:
    for y in arreglo2:
        if x == y:
            repetidos.append(x)

print "Los Repetidos son"
for z in repetidos:
    print z      

The output is: The Repeats are 2 4 6

I am creating an application where each user has their respective profile. These profiles are stored in a ArrayList. I have problems when creating a method to search for users registered or present in ArrayListit and I have to do it with 2 parameters Nombreand Apellido.

I have the following class:

import java.util.*;

public class Profilo {

    static String Nombre;
    static String Apellido;
    String Intereses;
    boolean visible;

    //contructor   
    public Profilo(String nombre, String apellido,String intereses,
            boolean visibilidad) {  
        this.Nombre= nombre;
        this.Apellido= apellido;
        this.Intereses= intereses;
        this.visible = visibilidad;

    }                  
    public String getNombre() {  
        return this.Nome;
    }            
    public String getApellido() {
        return this.Cognome;
    }

And another class that will contain the methods to login, register and search for users:

import java.util.ArrayList;
import java.util.Scanner;


public class PerfilManager {

    static ArrayList<Profilo> Users = new ArrayList();
    static Scanner sc = new Scanner(System.in);


     public static void Login() {
         //codigo
     }

     public static void Registrarse() {
        //codigo
     }

     public static void InizializaDati(){
         String nombre;
         String apellido;
         String intereses;
         boolean visibile;

         System.out.println("nombre:");
         nombre= sc.next();

         System.out.println("apellido:");
         apellido = sc.next();

         System.out.println("intereses:");
         intereses= sc.next();

         System.out.println("visible?(true/false)");  
         visibile = sc.nextBoolean();

         Perfil perfil= new Perfil(nombre,apellido,intereses,visibile);

         Users.add(perfil);
         System.out.println("peril creado!");

         ShowPerfil();
    }   

    public static void BuscaPerfil(String nome , String cognome) {
        for(int i = 0 ; i < Users.size();i++) {
            if(Users.get(i).visibile != false) {
                //muestra perfil
            } else {
                System.out.println("Este perfil es privado");    
            }
        }
    }
}

I have a string String str_one = "\uD83C\uDCA2"that paints a poker card for me but I would like to know if it is possible to generate all the cards with a cycle for.

I have tried to replace the last 2 characters, but could not. Also not having something like String str_two = "uD83CuDCA2"and then using the str_two.replaceAll("u", "\u")

I need to know if there is another way to generate the cards taking advantage of the pattern they have in their representation Unicode.

It doesn't have to be with strings, it can be with Character or with a hexadecimal representation, I just want to know if it is possible to generate the 52 cards taking advantage of the pattern they have.

Update:

I have used the string "symbol" as below for the creation of a letter and the set and get methods for "symbol" and "value", but later I will need the integer "codepoint", how do I get back from the string "symbol" to the integer "codepoint" ?

for (int c2 = 1, value=1; c2 <= 0xE; c2++, value++) {
    for (int c1 = 0xA; c1 <= 0xD; c1++) {
        if (c2!=0xC) {
            str = String.format("1F0%X%X", c1, c2);
            codePoint = Integer.parseInt(str, 16);
            symbol = String.format("%c", codePoint);

            cards.add(new Card (symbol, value));
        } else {
            value = 11;
        }
    }
    System.out.println();
}