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Accepted
zerokira
Asked: 2020-04-11 11:26:48 +0800 CST 2020-04-11 11:26:48 +0800 CST

如何在 AngularJs 中使用 $filter

  • 772

我怎样才能捕捉到$scope.personConOferta拥有的人oferta

<!DOCTYPE html>
<html>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.4/angular.min.js"></script>
<body>

<div ng-app="myApp" ng-controller="myCtrl">

  <div ng-repeat="person in personas">
     {{ person }}     
  </div>
</div>

<script>
var app = angular.module('myApp', []);
app.controller('myCtrl', function($scope, $filter) {
    $scope.personas = [
      {
         "Codigo": 1,
         "Name": "alberto",
         "Offerta": [
            {
              "precio": 10000,
              "lugar": "Medellin"
            },
            {
              "precio": 2000000,
              "lugar": "Bogota"
            }
         ]
      },
      {
         "Codigo": 2,
         "Name": "albertoPalacios",
         "Offerta": []
      }
    ]
    $scope.personConOferta = $filter('filter')($scope.personas, { Offerta.length > 0 }, true);
    $scope.personSinOferta = $filter('filter')($scope.personas, { Offerta.length == 0 }, true);
});
</script>

</body>
</html>

javascript

1 Answers

  1. Best Answer

    打开严格模式，这样它只会过滤你的精确匹配。这是通过在搜索条件后添加 true 来完成的。

    $scope.personAlberto = $filter('filter')($scope.personas, { Name: "alberto" }, true);
$scope.personAlbertoPalacios = $filter('filter')($scope.personas, { Name: "albertoPalacios" }, true);
    • 4