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Alejandro Carrera
Asked: 2020-09-04 22:38:14 +0800 CST 2020-09-04 22:38:14 +0800 CST

Python dice throw simulator

  • 772

I am trying to create a function that every time it is called, it will generate a list of 100 random rolls of a die using the random library.

import random

def dice():
    dado = []
    for i in range(100):
        dado.append(random.choice(range(1,7)))
        return dado

dice()

When I run the function, it only returns one value. On the other hand, when I do this:

def dice():
    dado = []
    for i in range(100):
        dado.append(random.choice(range(1,7)))
        print(dado)

It returns 100 lists. The first contains one number, the next two, and so on until the list 100 with 100 numbers is printed. As I pointed out, what I want is for a single list of 100 random numbers to be printed.

I want to point out that I am also interested in the fact that the resulting list can be plotted through a histogram, for example.

Any help or guidance is greatly appreciated. Thank you!

python

2 Answers

  1. Best Answer

    The error is in the "dice()" function, the return should have one less tab, so that it is returned when the loop ends.

    def dice():
  dado = []
  for i in range(100):
      dado.append(random.choice(range(1,7)))
  return dado

    I leave you an example in this link click

    • 2

  2. Dice rolls, you can take it as a sequence of random events, without complicating the problem by adding conditional probability, you could use the python library random:

    import random
# siendo N el numero de elementos de tu lista(numero de tiradas)
def dado(n):
    result=[]
    for i in xrange(0,n):
        result.append(random.randint(1, 6))
    return result

dado(10)
Out[0]:[2, 5, 1, 3, 4, 4, 5, 1, 1, 4]
    • 1