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Alan
Asked: 2020-12-15 09:32:17 +0800 CST 2020-12-15 09:32:17 +0800 CST

How to use strongly typed partial view inside another view?

  • 772

As a first option I am trying to create a strongly typed partial view. It would render inside of inside me _Layout.cshtmlsince the idea is that this partial view _UserInfoPartial.cshtmlwill be seen in all other views.

The second would be that from a parent view, for example from the home/index, render the aforementioned view.

How could I do to pass another modelto the daughter view?

Partial view model:

public class DatosUsuario
{
    public short Compania { get; set; }
    public Legajo LegajoUsuario { get; set; }
    public Funcion Funcion { get; set; }
    public string UsuarioNT { get; set; }
}

Parent view model:

public class Visita
{
    public short Compania { get; set; }
    public Local Local { get; set; }
    public DateTime Fecha { get; set; }
    public DateTime Periodo { get; set; }
    public Legajo LegajoGerente { get; set; }
    public Color Color { get; set; }
    public DateTime FechaCierre { get; set; }
}

This is my_Layout.cshtml

<body>
    <div class="container body-content">
        @RenderBody()
        <hr />
        @Html.Partial("_UserInfoPartial") @*aqui renderizo mi vista parcial*@
        <footer>
            <p>&copy; @DateTime.Now.Year</p>
        </footer>
    </div>

    @Scripts.Render("~/bundles/jquery")
    @Scripts.Render("~/bundles/bootstrap")
    @RenderSection("scripts", required: false)
</body>

I don't know why option to go, but it seems to me the most accurate to do it in it layoutsince it should be shown in all views.

c#

2 Answers

  1. Best Answer

    For this case it would be better to use a child action instead of just a partial view

    in a controller , say Home :

    [ChildActionOnly]
public ActionResult Child() {
    var model = new DatosUsuario();
    // ...
    return PartialView("_UserInfoPartial", model);
}

    ( [ChildActionOnly]it is not mandatory to call it, it is just so that it is not called directly as a normal action)

    and then in _Layout:

    @Html.Action("Child", "Home")

    @Html.Actionwrite in the layout the result of invoking the indicated action, and there you can specify the view and model you want to use

    • 7

  2. You can also put the partial view's model inside the parent view's model, and thus load it all at once. If you have to load it in all views, create a base model that all models inherit.

    @Html.Partial("_DatosUsuario", Model.DatosUsuario)
    • 1