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Jorge Ponti
Asked: 2020-07-26 13:42:23 +0800 CST 2020-07-26 13:42:23 +0800 CST

Replace dot with comma in Python 3

  • 772

Hello, I have a list of decimals that I converted to String, to be able to change the points for commas. But with "replace" it doesn't allow me to make the change, I'm doing it this way:

   for i in range(len(UCL)): #UCL de corte
      UCL[i].replace(".",",")
      print(UCL[i])

The original UCL list is of the form:

    ['2.363636368', '2.17391304', '3.875', '2.282828286', '2.383838386', '2.616161618', '2.363636368', '4.85', '4.75', '2.282828289', '2.616161618', '0.666666666', '3.0', '3.272727272', '2.434343439', '0.666666666', '0.666666666', '2.538461538', '0.666666666', '3.875', '2.616161618', '2.393939396', '0.666666666', '0.666666666', '0.666666666', '0.666666666', '2.383838384']

My idea is to print the same thing but change the dots to commas inside each string of the UCL list.

python

4 Answers

  1. Best Answer

    The problem is that it stris immutable and replacetherefore returns a copy of the string (it cannot modify the original string). You can create a new list using list compression with:

    nueva_UCL = [c.replace('.', ',') for c in UCL]

    If you prefer to use a fornormal and modify the original list you should do:

    for i in range(len(UCL)):
    UCL[i] = UCL[i].replace(".", ",")

    I assume you want to modify the list in addition to printing it. If you just wanted to print using commas, without modifying the original list, you could do (in Python 3):

    print(*(c.replace(".", ",") for c in UCL), sep='\n')

    Or for Python 2/Python3:

    for c in UCL:
    print(c.replace(".", ","))
    • 2

  2. Jorge, in Python strings like many other objects are immutable, do this:

    s = "1.4"
print(s.replace(".",","))
print(s)

    It will return this:

    1,4
1.4

    With this we confirm that it sis still worth "1.4". What needs to be done is to generate a new string by assigning:

    s = s.replace(".",",")
print(s)

    and now yes

    1,4

    In your example you should do the following:

    UCL[i] = UCL[i].replace(".",",")
    • 1

  3. I used this and if it worked for me:

    (tudato.replace(".",',') or :)

    after the replace you mention what you want to replace, after what you want to appear and the ormeans or change .or :for a,

    • 1

  4. It works for me:

    df["Close"] = df["Close"].str.replace(".", ",")
    • 0