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sirdaiz
Asked: 2020-06-09 23:58:30 +0800 CST 2020-06-09 23:58:30 +0800 CST

Get only 2 decimals

  • 772

I have the following js:

var array = ["paco", "185.6687", "lucas", "1365.2541"]

<div ng-repeat="val in array">
   {{val}}
</div>

I know that if it were a number, it would {{val | number:2}}work, but if I have that array, how do I make it so that it only shows me 2 decimal places?

angularjs

2 Answers

  1. Best Answer

    In Angular you can create a formatting function, and then instead of directly outputting the variable, output it to the formatting function (passing the variable as an input parameter).

    In your particular case, you want a function that if the input is a string, leave it as such, but if it is a number, only leave two decimal places. This could be done with a simple function:

    function formateaValor(valor) {
  // si no es un número devuelve el valor, o lo convierte a número con 2 decimales
  return isNaN(valor) ? valor : parseFloat(valor).toFixed(2);
}

    You can integrate this into AngularJS as follows:

    var app = angular.module("miApp", []);
app.controller("miCtrl", function($scope) {
  $scope.array = ["paco", "185.6687", "lucas", "1365.2541"];
  $scope.miFormato = function(valor) {
    return isNaN(valor) ? valor : parseFloat(valor).toFixed(2);
  }
});
    <script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>

<body ng-app="miApp" ng-controller="miCtrl">
  <div ng-repeat="val in array">
    {{ miFormato(val) }}
  </div>
</body>

    • 2 
  2. var n1 = array[1].toFixed(2);
var n2 = array[3].toFixed(2);

    So it will only catch you 2 decimals.

    for(int i = 0;i < array[].length;i++){
 if(array[i].isNaN(array[i])) {
    array[i] = array[i].toFixed(2);
  }else{

 }
}

    Something like this sounds like it might work for you

    • 0