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Accepted
Eduardo Sebastian
Asked: 2020-04-20 06:27:20 +0800 CST 2020-04-20 06:27:20 +0800 CST

Problem in loop for JavaScript

  • 772

I have the following code:

leaderboard.lengthIt is defined from the server and in my case it is 12

var l = leaderboard.length;
var i = 0;

for ( ; i < l; i++) {   
    var o = (i + 1) + ". " + name;
}

This will show me the position of the players from 1 to 11

But my problem is that even if leaderboard.lengthit is 11, I want it to show all the positions, but at position 9 it does not show the number 9, that is, only:

1 - Player 1
2 - Player 2
3- Player 3
4- Player 4
5- Player 5
6- Player 6
7- Player 7
8- Player 8
- Player 9
10 - Player 10
11 - Player 11

javascript

3 Answers

  1. You can use the ternary operatorA ? B : C

    l = leaderboard.length;
i = 0;

for( ; i < l; i++ ) {

  o = ( i == 8 ) ? ( name ) : ( (i + 1) + ". " + name );
}

    This operator evaluates A and, if is true, returns B. Otherwise, it returns C.

    • 5
  2. Best Answer

    Or you could use aIF

    var l = leaderboard.length;
var i = 0;

for ( ; i < l; i++) {

 if(i==8){
 var o = ". " + name;
 }else{
 var o = (i + 1) + ". " + name;
 }
    • 3

  3. Keep in mind that you are evaluating from 0, which means that the results will be in the range of 0~11 < 12, so the values ​​from 1 to 12 will be displayed, I leave you the result in the following example:

    var l = 12;//leaderboard.length;
var i = 0;
var name = "Jugador n";

for ( ; i < l; i++) {   
    var o = (i + 1) + ". " + name;
    console.log(o);
}

    the correct way would be:

    var leaderboard="123456789012";
var name = "Jugador n";

for (i = 1; i < leaderboard.length; i++) {
 var o = (i==9) ? name : i+". "+name;
 console.log(o);
}

    • 1