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Goyo
Asked: 2020-03-26 11:36:36 +0800 CST 2020-03-26 11:36:36 +0800 CST

Round decimal in c# always to the greater number

  • 772

I'm trying to round a decimal number, but what normally happens is that if the number is assuming 40.40it stays in 40, and if it is it 40.60goes up, 41my code is as follows:

decimal price = 13224.60m;
int aux = (int) Math.Round(Convert.ToDouble(price), 0, MidpointRounding.ToEven);

like this the code if I execute it gives me the result 13225, but if I change the value of pricea 13224.40:

decimal price = 13224.40m;
int aux = (int) Math.Round(Convert.ToDouble(price), 0, MidpointRounding.ToEven);

gives me the result 13224, and what I want is that I always round it up, that is, that in any of the two cases I round it to 13225.

is there any way to do that ? And if there is, how would the implementation be?

c#

2 Answers

  1. Best Answer

    You can use:

    decimal price = Math.Ceiling(13224.40m);
    • 5

  2. There are two methods in C#, the first one that rounds the input value to its immediate largerMath.Ceiling(decimal) integer , and also that rounds the input value to its immediate smaller integer , see these examples:Math.Floor(decimal)

    Console.WriteLine("{0,7} {1,16} {2,14}", 
                     value, Math.Ceiling(value), Math.Floor(value));

//         Value          Ceiling          Floor
//       
//          7.03                8              7
//          7.64                8              7
//          0.12                1              0
//         -0.12                0             -1
//          -7.1               -7             -8
//          -7.6               -7             -8
    • 4