Home / Questions / 563583
Accepted
Alberto Julio Arce Escolar
Asked: 2022-10-22 08:57:49 +0800 CST 2022-10-22 08:57:49 +0800 CST

how to extract data from a string

  • 772

How can I extract the data that is inside the brackets with their respective position?

let str = 'Aqui esta [pepe] y [pepito]';

resultado=str.split(" ")

[ 'Aqui', 'esta', '[pepe]', 'y', '[pepito]' ]

in this case you should get the word pepe in position 2 and 4 in pepito to be able to save an object with the position and the word

javascript

3 Answers

  1. You can try to replace the characters in this way. This in case the structure is not changing.

    let str = 'Aqui esta [pepe] y [pepito]';

resultado = str.split(" ").map(x => {

  let dato = x
  try {

    dato = dato.replace('[', "[\"").replace("]", "\"]")
    dato = JSON.parse(dato)

  } catch (e) {
    console.log('ignorado', x)
  }

  return dato

})
console.log(resultado)

    • 0
  2. Best Answer

    let str = 'Aqui esta [pepe] y [pepito]';
let objetoProcesado = [];
str.split(" ").map((valor, indice) => {

  let dato = valor;
  try {
    // Tenemos dos restricciones:
    // 1. Que tenga [ ] en la posición inicial y posición final de la palabra.
    // 2. Que solo exista 1 "[" y 1 "]"
    let condicionInicial = dato.toString().indexOf('[') == 0;
    //console.log('condicionInicial -> ',condicionInicial);
    let condicionFinal = dato.toString().indexOf(']') == dato.toString().length -1;    
    //console.log('condicionFinal -> ',condicionFinal);    
    //console.log('palabra procesada: ', dato);
    
    let cantidadBracketsApertura = 0;
    let cantidadBracketsClausura = 0;
    for(let index = 0; index <= dato.toString().length; index++)
    {
        let character = dato.toString().charAt(index);
        if(character == '[')
        {
            cantidadBracketsApertura++;
        }
        if(character == ']')
        {
            cantidadBracketsClausura++;
        }
    }

    let condicionBrackets = (cantidadBracketsApertura == 1 && cantidadBracketsClausura == 1);
    
    if (condicionInicial && condicionFinal && condicionBrackets)
    {
        let palabraSinBrackets = dato.toString().replace('[','').replace(']','');
        objetoProcesado.push({'palabra':palabraSinBrackets, 'posicion':indice});
    }
  } catch (e) {
    console.log('error al procesar:', dato);
  } 

});

console.log('Objeto Procesado: ');
console.log(objetoProcesado);

    Suggested reading:

    https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Array/map

    • 0

  3. you can do it like this:

    let str = 'Aqui esta [pepe] y [pepito]';
arr = str.split(" ")

for (x in arr )
 if(arr [x].includes("]"))
    arr [x] = [ arr [x].replace(/\[|\]/g,"")]
 
console.log(arr )

    • 0