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Jeus Jimenez
Asked: 2022-10-22 02:13:13 +0800 CST 2022-10-22 02:13:13 +0800 CST

Error comparing two numbers in a bash script

  • 772

I am making a script that you put two numbers and it tells you if they are divisible. But it gives me an error. I am making a script that you put two numbers and it tells you if they are divisible. But it gives me an error. THE SCRIPT CODE:

enter image description here

#!/bin/bash



read -p "Numero 1: " num1

read -p "Numero 2: " num2

cero=0

$op=$(($num1%$num2))

if [$op -eq $cero] 

then

echo "ES DIVISIBLE"

else

echo "NO ES DIVISIBLE"

fi

/divisibles.sh

Numero 1: 4

Numero 2: 4

./divisibles.sh: línea 6: =0: orden no encontrada

./divisibles.sh: línea 7: [: falta un `]'

NO ES DIVISIBLE
linux

2 Answers

  1. Best Answer
    • opwhen initializing it goes without the$
    • You are missing a ;in the conditional if:
    #!/bin/bash

read -p "Numero 1: " num1
read -p "Numero 2: " num2

cero=0

op="$(( $num1%$num2 ))"

if [ "${op}" -eq "${cero}" ]; then
    echo "ES DIVISIBLE"
else
    echo "NO ES DIVISIBLE"
fi

    Result:

    $ bash numbers.sh 
Numero 1: 2
Numero 2: 1
ES DIVISIBLE

$ bash numbers.sh 
Numero 1: 1
Numero 2: 2
NO ES DIVISIBLE
    • 3

  2. It may be that your problem is that instead of declaring the variable, that is, creating it, you are calling it as if it already existed. The code should be something like this:

    #!/bin/bash


read -p "Numero 1: " num1

read -p "Numero 2: " num2

cero=0#Aqui quitamos el dollar para que en vez de llamarla el programa interprete que la estas creando

let op=$num1%$num2#Igual aqui, he cambiado el comando a ver si asi te va

if [$op == $cero]; #Tambien pon el punto y coma importante que se nos habia olvidado XD. Pones el igual por si acaso tienes un problema de tipo de variables

then

echo ES DIVISIBLE

else

echo NO ES DIVISIBLE

fi

    Tell me if it works for you because I haven't been able to test it

    • 0