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Ivannava
Asked: 2022-10-21 12:58:49 +0800 CST 2022-10-21 12:58:49 +0800 CST

how to get the last part of a url in js

  • 772

Several urls arrive in an array from which I want to extract the last part

http://130.10.1:8087/tests/downloadFile/file.txt

so far I have only managed to get what goes before the file name, but what I want is to only get the name of said files file.txt

var url = "http://130.10.1:8087/pruebas/downloadFile/archivo.txt";

var ultimaPosicion = url.lastIndexOf('/');
var nivelAnterior = url.substr(0, ultimaPosicion);
console.log(nivelAnterior);

I'm new to JS, can you help me please?

javascript

3 Answers

  1. Best Answer

    With the .split() method you can save a string in an array, dividing it according to the char you send as a parameter, if you send a '/' as a parameter it will split the string using / as a reference, we do a split to the string, and we take the last value of the array, which will return the value you are looking for

    var url = "http://130.10.1:8087/pruebas/downloadFile/archivo.txt";
const arr = url.split('/')
console.log(arr[arr.length-1]) // retorna archivo.txt

    • 1

  2. This may also work for you:

    var url = "http://130.10.1:8087/pruebas/downloadFile/archivo.txt";
console.log(url.slice(url.lastIndexOf('/') + 1))

    where what we do is, through the slice() method we extract the piece of string that starts at the position obtained with lastIndexOf() until the end, and we add +1 to it to avoid the bar/

    • 0

  3. You could use split("/")to separate the string at each /it finds. After this you should go to the last position of the array as follows:

    ultimaPosicion[ultimaPosicion.length - 1]

    Your code would be like this:

    var url = "http://130.10.1:8087/pruebas/downloadFile/archivo.txt";

var ultimaPosicion = url.split("/");
var nivelAnterior = ultimaPosicion[ultimaPosicion.length - 1];
console.log(nivelAnterior)

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