I have a data source with a "timestamp" column that reflects the time as follows:
2022-08-17T19:20:41.218+0200
My question is if there is any direct way, that does not need a loop that goes through all the files (there are tens of thousands a day), to transform that date format into a more friendly one of the style:
2022-08-17 19:20
I have tried the following, among other things, with no positive results:
Rango.Columns("F").NumberFormat = "mm/dd/yyyy HH:mm"
Rango.Columns("F").NumberFormat = "mm/dd/yyyy hh:nn"
Thanks for the help.
I finally got it like this:
I thought that making a loop would take a long time given the file extension, but it turns out not, it's been a few seconds.
I use the Mid function to collect the portions of the String that interest me (date, hour and minute), store it in a String and rewrite each cell with that new format.