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Mario16
Asked: 2022-08-02 22:30:22 +0800 CST 2022-08-02 22:30:22 +0800 CST

How can I order this array from smallest to largest?

  • 772

I have been searching for various alternatives but I am not able to sort the array from least to greatest without sort(). How can I detect?

serie = [4,3,2,1,6,8,7]

for i in serie:
    if i > 0:
        i = i - 1
        print(i)
python

1 Answers

  1. Best Answer

    Good day,

    You could loop through the list with 2 loops forone to loop through all the values ​​and one to loop from the next position of the current iteration to the end, compare the numbers and if larger swap them

    serie = [4,3,2,1,6,8,7]

for i in range(len(serie)):
    for j in range(i + 1, len(serie)):
        if serie[i] > serie[j]:
            serie[i], serie[j] = serie[j], serie[i]

print(serie)

    This returns:

    [1, 2, 3, 4, 6, 7, 8]

    Another option would be to create a new list, compare each value of the series with the first value, in case of finding a smaller one, obtain it, if there is no smaller one then the smaller one would be the first element, remove that element from the original series and add it with appendto the new list. At the end of the original list there will be 0 elements and in the new list you will have all the elements sorted

    serie = [4,3,2,1,6,8,7]
nueva_lista = []

while serie:
    minimo = serie[0]
    for x in serie: 
        if x < minimo:
            minimo = x
    nueva_lista.append(minimo)
    serie.remove(minimo)    

print(nueva_lista)

    This returns:

    [1, 2, 3, 4, 6, 7, 8]
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