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Accepted
Darinel Cigarroa
Asked: 2022-06-21 21:20:49 +0800 CST 2022-06-21 21:20:49 +0800 CST

Add a new key and value to all objects in an array of objects?

  • 772

Hello everyone, thank you very much in advance for your answers and comments, I am trying the following:

I have an array of Objects in which I want to add a new key and value to all the objects, I have the following object:

const pension = [
  {cat_bank_id: 91,cat_discount: 1,clabe: "901",curp: "ASDA",name: "asda",percentage: "12"},
  {cat_bank_id: 92,cat_discount: 1,clabe: "902",curp: "ASDB",name: "asdb",percentage: "12"}
];

I want to achieve the following:

const pension = [
  {cat_bank_id: 91,cat_discount: 1,clabe: "901",curp: "ASDA",name: "asda",percentage: "12", employee_id: 212},
  {cat_bank_id: 92,cat_discount: 1,clabe: "902",curp: "ASDB",name: "asdb",percentage: "12", employee_id: 212}
];

I am trying as follows:

const pension = [
  {cat_bank_id: 91,cat_discount: 1,clabe: "901",curp: "ASDA",name: "asda",percentage: "12"},
  {cat_bank_id: 92,cat_discount: 1,clabe: "902",curp: "ASDB",name: "asdb",percentage: "12"}
];
const employee_id = 212;

const test = pension.map(pension => {
    return pension.key3 = employee_id;
});
console.log(test)
javascript

1 Answers

  1. Best Answer

    You must create a new object or append it. The spread operator can be useful.

    const pension = [
  {cat_bank_id: 91,cat_discount: 1,clabe: "901",curp: "ASDA",name: "asda",percentage: "12"},
  {cat_bank_id: 92,cat_discount: 1,clabe: "902",curp: "ASDB",name: "asdb",percentage: "12"}
];
const employee_id = 212;

const test = pension.map(pension => {
    // spread operator ( ... )
    return {...pension,employee_id };
});
console.log(test)

    Another way to do it:

    const pension = [
  {cat_bank_id: 91,cat_discount: 1,clabe: "901",curp: "ASDA",name: "asda",percentage: "12"},
  {cat_bank_id: 92,cat_discount: 1,clabe: "902",curp: "ASDB",name: "asdb",percentage: "12"}
];
const employee_id = 212;

const test = pension.map(pension => {
    pension['employee_id']=employee_id 
    return pension;
});
console.log(test)

    • 0