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Accepted
Enrique Espinosa
Asked: 2022-05-07 21:10:31 +0800 CST 2022-05-07 21:10:31 +0800 CST

Why do I get a syntax error in the constructor when placing "public string $variable"?

  • 772

I have a problem with a constructor that I am trying to create in php, I don't understand why I get a syntax error when I write the constructor in this way:

enter image description here

I don't understand is it due to the version of php or what am I doing wrong, now if I remove all the public on screen from the constructor it prints the following error:

Catchable fatal error: Argument 1 passed to Product::__construct() must be an instance of string, string given

I don't understand that error either, my class and my function are being called in this way:

$producto = new Producto('Teclado', 200, true);
$producto->mostrarProducto();

echo "<pre>";
var_dump($producto);
echo "</pre>";
php

1 Answers

  1. Best Answer

    The publicones in the parameters are too much for you, that's clear.

    And the types ( string, int, bool) are also left over if the version of PHP running the script is older than PHP 7 .

    public function __construct($nombre, $precio, $disponible) {
    //
}

    Prior to PHP 7, type hinting could only be used to coerce object and array types. In the case of your constructor, an object of class string is expected, but a (scalar) string is being passed to it.

    https://stackoverflow.com/questions/4103480/how-to-resolve-must-be-an-instance-of-string-string-given-prior-to-php-7

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