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Jorius
Asked: 2020-02-17 17:43:35 +0800 CST 2020-02-17 17:43:35 +0800 CST

How to sort an array of numbers in javascript?

  • 772

I found this simple problem in javascript, when making a number sortby one array, it did not order them correctly from smallest to largest:

var arrayStrings = ['Banana', 'World', 'Apple', 'Chocolate']
var arrayNumbers = [10, 8, 9, 5, 3, 78, 23]

console.log(arrayStrings.sort()) // Lo ordena bien
console.log(arrayNumbers.sort()) // Lo ordena mal

javascript

3 Answers

  1. Best Answer

    I was able to solve it this way:

    var arrayNumbers = [10, 8, 9, 5, 3, 78, 23]

// Sintaxis ES5
console.log(arrayNumbers.sort(function (a, b){
    return a - b;
}))

// Sintaxis ES2015
console.log(arrayNumbers.sort((a, b) => a - b ))

    It can also be done implicitly by doing one prototypeof the following:

    var arrayNumbers = [10, 8, 9, 5, 3, 78, 23]

Array.prototype.sortNumbers = function(){
    return this.sort(
        function(a,b){
            return a - b
        }
    );
}

console.log(arrayNumbers.sortNumbers())

    • 7

  2. I think that programmers in general complicate your life in a bad way. The thing is much simpler.

    function comparar(a,b){return a - b}

ejemplo=new Array(10, 8, 9, 5, 3, 78, 23)

function ordenar(){

  ejemplo1=ejemplo.sort(comparar)

  alert('el orden de los números es  ' + ejemplo1[0] + '-' + ejemplo1[1] + '-' + ejemplo1[2] + '-' + ejemplo1[3] + '-' + ejemplo1[4] + '-' + ejemplo1[5] + '-' + ejemplo1[6]);
}

//Llamando a la función ordenar() aparecería una cuadro emergente con el texto "el orden de los números es 3-5-8-9-10-23-78"

ordenar();

    • 2 
  3. var arrayNumbers = [10, 8, 9, 5, 3, 78, 23];

var orden = arrayNumbers.sort((a,b)=>{
    return a-b;
 }); 
console.log(orden);

    It is the same method only that you make the comparison of which is less and changes

    • 0