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TwoDent
Asked: 2020-01-28 11:37:44 +0800 CST 2020-01-28 11:37:44 +0800 CST

URI is not hierarchical (JAVA)

  • 772

I'm having a pretty awkward problem. I generated a test executable JAR file, and it is generating the following error:

Exception en thread "AWT-EventQueue-0" java.lang.IllegalArgumentException: URI is not hierarchical
    at java.io.File.<init>(Unknown Source)
    at Trivia.Interfaz.<init>(Interfaz.java:74)  <= mi codigo

enter image description here

Starting with the internal schematic of my project. I have the images of the program saved as separate packages.

enter image description here

The package where I have the images is called "assets".

Well, in the code when I load the images I have it written as follows:

Image img = ImageIO.read(new File(getClass().getResource("/assets/panama-16.png").toURI()));

Doing it this way doesn't give any kind of error and the program runs normally in the netbeans IDE, but the problem starts when I generate the JAR executable. And I read somewhere that this is caused by the reason that when generating the executable, what Netbeans does is compress all those files (ZIP), and of course, with that things change drastically in terms of the use of the URL .

My question is: How can I make all those images run normally from the JAR file inside a project package without any problem?

java

3 Answers

  1. Best Answer

    The problem is that getResourcethe returns a URL. When the URL points to a file on the file system, there is no problem creating a Filewith them, but if it is a resource inside a jar then it is not appropriate to open it as File.

    My favorite is to use always Class.getResourceAsStream(String), which returns a InputStreamwhere you can get the resource from.

    Since ImageIO.readit has an overload that accepts a InputStream, do:

    Image img = ImageIO.read(getClass().getResourceAsStream("/assets/panama-16.png"));
    • 5

  2. Inside the .jar you cannot use File. Use ImageIO.read(InputStream io) instead.

    Image img = ImageIO.read(getClass().getResourceAsStream( "/assets/panama-16.png" ));

    The reason you can't use a file descriptor is that the data inside a .jar is not actually a file. Be careful , the path inside the .jar has to be from the root of the jar, so start with /.

    • 2

  3. I use these two for images that are in the jar:

    Image imga = new ImageIcon(getClass().getResource("/res/img/imagen.jpg")).getImage();

ImageIcon img=new ImageIcon(NombreClase.class.getResource("/res/img/imagen.jpg"));
    • 2