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codeman
Asked: 2022-06-10 05:45:25 +0800 CST 2022-06-10 05:45:25 +0800 CST

Rename part of Bash file

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people how are you

How can I do to automatically rename a list of files, only modifying the date that it has in the name of the file, for the current day, without modifying the rest of the values??

I have a file that has the list, its content would be like this:

DASH_20210608175132_0000.msg
DASH_20210608175132_0001.msg
DASH_20210608175132_0002.msg

Manually it would be:

mv DASH_20210608175132_0000.msg DASH_`date +"%Y%m%d"`175132_0000.msg
mv DASH_20210608175132_0001.msg DASH_`date +"%Y%m%d"`175132_0001.msg
mv DASH_20210608175132_0002.msg DASH_`date +"%Y%m%d"`175132_0002.msg
mv DASH_20210608175132_0003.msg DASH_`date +"%Y%m%d"`175132_0003.msg

In this way I only change what I need the date in the file mask.

But I would like to automate this procedure, how could I do it?

linux

1 Answers

  1. Best Answer

    You could separate the file names with a cut:

    # ls DASH_*.msg | while read f; do
cat ficheros.txt | while read f; do
        echo "Antes: $f"

        d="$(date +'%Y%m%d')"

        f_2="$(echo $f | sed -e "s/_[0-9]\{8\}/_${d}/g")"

        echo "Despues: $f_2"
        # mv $f $f_2
done

    The commented lines is because I don't know if you are going to read the list from a file or execute it with a ls. Either way, you can always pass an whileafter to it with a pipe.

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