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ortiga
Asked: 2020-04-09 03:59:51 +0800 CST 2020-04-09 03:59:51 +0800 CST

get the name of a parameter in python

  • 772

good I have the following function:

def http1(response):

    respone.????
    ...

I call it as follows, passing it a function that also receives a parameter

http1(http2(parametro))

My question is how do I get the parameter name of the http2 function so that I can work with it in the http1 function???

python

1 Answers

  1. Best Answer

    First, "get parameter name" is useless, "parameter name" AKA "variable" is just that, a name associated with an object in memory. What you need is not the name of the parameter, but a reference to the object passed as the argument.

    As you say it is impossible, it http2receives the output ofhttp1 , unless it http1returns some reference to responseyou will not be able to access from http2. If this is not the case:

    • Make it http1also return a reference to response:

      class Response:
    foo = 7

def http1(response):
    response.foo += 3
    return "Hola", response

def http2(arg):
    http1_resp, response = arg
    print(response.foo)

response = Response()
http2(http1(response))

      def http1(response):
    response[0] += 3
    return "Hola", response

def http2(arg):
    http1_resp, response = arg
    print(response)

http2(http1([7, 2]))

    • Pass http2a reference to the function and the arguments to pass to the function and execute it inside http2:

      class Response:
    foo = 7

def http1(response):
    response.foo += 3
    return "Hola"

def http2(func, response):
    http1_resp = func(response)
    print(response)

response = Response()
http2(http1, response)

      def http1(response):
    response[0] += 3
    return "Hola", response

def http2(func, response):
    http1_resp = func(response)
    print(response)

http2(http1, [7, 2])
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