Home / Questions / 295164
Accepted
RazerJs
Asked: 2020-09-21 14:12:02 +0800 CST 2020-09-21 14:12:02 +0800 CST

Convert a fraction to mixed number javascript

  • 772

The goal of the function is to convert from a fraction to a mixed number. So far I can get the integer part but I have problems simplifying the dividend and the divisor of the number (for example from 6/9to 2/3). Thank you

function convertirFraccion(s) {
    s = s.split('/').map(a => Number(a))
    let modulo = s[0] % s[1]
    let resto = modulo / s[1]
    let numeral = Math.floor(s[0] / s[1])
    return modulo == 0 ? numeral : `${numeral} ${modulo}/${s[1]}`
}

console.log(convertirFraccion('24/9'));

javascript

2 Answers

  1. Best Answer

    The code you have works very well, you only have a problem when doing the simplification of the dividend and the divisor.

    In the simplification you reduce both numbers by dividing them by their prime factors until they are both primes of each other (have no prime factors in common).

    For this, in your code you verify the result of modulo, if it is 0 it implies that the division is exact and only an integer result is shown.

    If not, you will have to decompose the numbers, for that you start by checking the module of both numbers starting with 2 up to half of the dividend, (it could be more optimal with the square root since the largest number that can divide exactly a number is less than or equal to its square root).

    Every time both modules result in 0, you divide the number by the current factor. This factor is then increased.

    At the end to show the mixed number you can check if the integer part is greater than 0, otherwise there is no need to show it.

    return `${numeral > 0 ? numeral+' ' : ''}${modulo}/${s[1]}`

    The code is as follows:

    function convertirFraccion(s) {
    s = s.split('/').map(a => Number(a))
    let modulo = s[0] % s[1]
    let resto = modulo / s[1]
    let numeral = Math.floor(s[0] / s[1])
    
    if(modulo!=0){
      act=2;
      while(act<s[1]/2){
        if(modulo%act==0 && s[1]%act==0){
          modulo/=act; 
          s[1]/=act;
        }
        act++;
      }
      return `${numeral > 0 ? numeral+' ' : ''}${modulo}/${s[1]}`
    }
    else
      return numeral
}
//ejemplos
console.log(convertirFraccion('24/9'));
console.log(convertirFraccion('4/3'));
console.log(convertirFraccion('28/7'));
console.log(convertirFraccion('2/36'));
console.log(convertirFraccion('53/83'));

    This is just a rough way to solve it, I think it can be optimized a little more, greetings.

    • 5

  2. The problem was not thought of in the event that they inserted one of the negative numbers or both... which complicates things a bit, I leave this function here... by brute force but which checks all the cases

    function convertirFraccion(s) {
    s = s.split('/').map(a => +a)
    const division = s[0] / s[1]
    let modulo = s[0] % s[1]
    if (s[1] == 0) {
    throw new Error('ZeroDivisionError')
    }
    if (modulo == 0) {
        return `` + s[0] / s[1]
    } else if (division < 1 && division > -1) {
        let sinNumeral = simplificarFraccion(s[0], s[1])
        return sinNumeral
    } else {
        let numeral = s[0] / s[1]
        numeral > 0 ? numeral = Math.floor(numeral) : numeral = Math.ceil(numeral)
        let numeros = simplificarFraccion(modulo, s[1])
        numeros = numeros.split('/').map(a => {
            return +a < 0 ? a * -1 : +a
        }).join('/')
        return `${numeral} ${numeros}`
    }
}

function simplificarFraccion(modulo, divisor) {
    let signo = modulo / divisor;
    if (modulo < 0) modulo *= -1
    if (divisor < 0) divisor *= -1
    let act = 2;
    while (act <= divisor / 2) {
        if (modulo % act == 0 && divisor % act == 0) {
            modulo /= act;
            divisor /= act;
            act = 1
        }
        act++
    }
    return signo > 0 ? `${modulo}/${divisor}` : `-${modulo}/${divisor}`
}

console.log(convertirFraccion('-98/-91'));
console.log(convertirFraccion('-3/-7'));
console.log(convertirFraccion('4/12'));
console.log(convertirFraccion('89/-12'));
console.log(convertirFraccion('0/-12'));
console.log(convertirFraccion('33/11'));
console.log(convertirFraccion('33/0'));

    • 1