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RazerJs
Asked: 2020-09-12 11:44:49 +0800 CST 2020-09-12 11:44:49 +0800 CST

Remove numbers from an array if they repeat

  • 772

I am making a function that eliminates the repeated numbers of an array (eliminates them completely and only returns the one that is not repeated). This is my function that is doing the opposite. For the example of [1, 2, 1 ] returns [1] :

function noRepetido(numeros) {

    const numero = numeros.filter((numero, i, self) => (
        self.indexOf(numero) != i
    ))
    return numero;
}

console.log(noRepetido([1, 2, 1]));

If instead of using the distinct operator !=I use the equals, ===it returns the array without repeating any number [1,2] for the example.

javascript

4 Answers

  1. Best Answer

    Excuse me, in the morning they already gave you a similar answer, you just had to adapt it:

    function noRepetido(array){
  const strUnique = [...new Set(array)];
  return strUnique.filter(
    el => array
    .filter(
      char => el === char).length === 1
    );
}

console.log(noRepetido([1, 2, 1, 4, 3, 3]));

    Credits to its author, then I'll give you a reward.

    Remove repeated characters in a string with javascript

    • 8

  2. You can use it like this:

    let repetidos= [ 1,2,3,4,4,1,5,2,6];
let sinRepetir=[];
sinRepetir= repetidos.filter((valorActual, indiceActual, arreglo) => {
    return arreglo.findIndex(valorDelArreglo => JSON.stringify(valorDelArreglo) === 
    JSON.stringify(valorActual)) === indiceActual
});

console.log(sinRepetir)

    • 4

  3. You can fix it by looping through the array just once, like this:

    • You create an object ( eg: checkeds) where you register the numbers already controlled.
    • By traversing the array, you validate that the number is not in the object and that it is not in the array again.

    Example:

    function noRepetido(numeros) {
  let checkeds = {};
  return numeros.filter((num, i) => {
    let unique = !checkeds[num] && !numeros.includes(num, i + 1);
    checkeds[num] = true;
    return unique;
  });
}

console.log(noRepetido([1, 2, 1, 3, 4, 4]));

    • 3

  4. You can make use of Set and remove the repeated elements.

    let arr = [1,2,3,3,4,5,5,5,5,5];

let unicos = new Set(arr);

console.log("Unicos: ", [...unicos]);

    • 1