Home / Questions / 279406
Accepted
JoseMgz_Ux
Asked: 2020-07-17 10:42:28 +0800 CST 2020-07-17 10:42:28 +0800 CST

Firebase database - Android Studio

  • 772

I am making an application for an inventory of item loans (keyboards, mouse...) I ask for Carrera, name to whom I lend, item, date, received in case they return and status (Loaned or delivered), ok help me out video to make the database with FIREBASE.

The authentication works great but what interests me the most is the database. The application when I give it a registration tells me "Successful registration" but does not save anything.

I would really appreciate the help, please.

(various variables declared)

private DatabaseReference Clases;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_prestamo);

    Clases = FirebaseDatabase.getInstance().getReference("Clases");

    Estudiante = (EditText)findViewById(R.id.edtEstd);
    Articulo = (EditText)findViewById(R.id.edtArt);
    Recibido = (EditText)findViewById(R.id.edtRecibido);
    Fecha = (EditText)findViewById(R.id.edtFecha);
    Estado = (Spinner)findViewById(R.id.spnEstado);
    btRegistrarP = (Button)findViewById(R.id.btRegistroP);
    ayuda = (ImageButton)findViewById(R.id.btnAyuda);


}
public void RegistrarPrestamo(){
    String estud = Estudiante.getText().toString();
    String artic = Articulo.getText().toString();
    String fech = Fecha .getText().toString();
    String estado = Estado.getSelectedItem().toString();
    String recib = Recibido.getText().toString();

    if(!TextUtils.isEmpty(estud)){
        String id = Clases.push().getKey();
        Clases lai= new Clases(id,estud, artic,fech,estado,recib);
        Clases.child(id).setValue(lai);

        Toast.makeText(this, "Registro exitoso", Toast.LENGTH_SHORT).show();
    }else{
        Toast.makeText(this, "Introduzca un Estudiante", Toast.LENGTH_SHORT).show();
    }
}
public void Ayuda(){
    Toast.makeText(this, "LLene este cuadrante en caso de estar recibiendo un Artículo", Toast.LENGTH_LONG).show();
}

public void onClick(View view) {

    switch (view.getId()) {
        case R.id.btRegistroP:
            RegistrarPrestamo();
            break;

        case R.id.btnAyuda:
            Ayuda();
    }
}
android

2 Answers

  1. Best Answer

    The reference is fine and the code writing and initializing the reference is fine.

    It can be for two things

    • You didn't enable internet permission in your Manifest

       <uses-permission android:name="android.permission.INTERNET" />

    • You have your Firebase rules for authenticated user write only

    On the other hand, in terms of design, I would advise you to use variable names in lower case and not in upper case, you can confuse them with a class or object

    private DatabaseReference clasesRef;

    As I see that you also have an instance of Clases, the problem may be that it Clasesis declared as DatabaseReference, and Clasesas Clases, I suggest you change the name of your DatabaseReferenceto lower case as I proposed above .

    • 1

  2. First get the main database reference

    private DatabaseReference Clases;

@Override
protected void onCreate(Bundle savedInstanceState) {
    Clases = FirebaseDatabase.getInstance()
}

public void RegistrarPrestamo(){
    String id = Clases.child("Clases").push().getKey();
    Clases lai= new Clases(id,estud, artic,fech,estado,recib);
    Clases.child("Clases").child(id).setValue(lai);
}

    Firebase Guide

    • 0