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E-Rick
Asked: 2020-06-19 00:12:09 +0800 CST 2020-06-19 00:12:09 +0800 CST

How to compose a date from two different dates?

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I put this pseudocode that I know doesn't work to explain what I want to do:

resultado = 0 
fecha1 = 2000,1,1 2:21 
fecha2 = 2001,1,1 4:44 
resultado = fecha1-getAño(); 
resultado = fecha2-gerHora() 
dump(resultado) // 2011,1,1 T4:44

From what I'm seeing, I have to decompose the dates into year, month, days, hour, minute, second, and then recompose them into one...

Isn't there another more direct way? There has to be an easier way!!

php

1 Answers

  1. Best Answer

    One of the class's constructors DateTimeneeds to receive a string"yyyy-MM-dd hh:mm:ss" type. Playing with the function formatof the objects of the class DateTimeyou can build a third DateTimewith the union of the date and the time.

    $fecha = new DateTime('2017-03-14');
$hora = new DateTime('13:37:42');

$fecha_hora = new DateTime($fecha->format('Y-m-d') . ' ' . $hora->format('H:i:s'));

echo $fecha_hora->format('Y-m-d H:i:s');

    EDIT

    You could also do the reverse. Starting from an initial date, break it down to get the date on the one hand and the time on the other. As you can see the function formatis very useful.

    $fecha_hora = new DateTime('2017-03-14 13:37:42');

$hora = new DateTime($fecha_hora->format('H:i:s'));
$fecha = new DateTime($fecha_hora->format('Y-m-d'));

echo 'Fecha: ' . $fecha->format('Y-m-d');
echo '<br>';
echo 'Hora: ' . $hora->format('H:i:s');
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