How to order corresponding menus and submenus in Java + PrimeFaces?

Ok, certainly the way you have the data is correct in what happens to you. Currently your menu creation algorithm loops through the list itself for each iteration. The problem is that by looping through your list, you're obviously duplicating instances and that causes your menu to look the way it does.

The idea is the following:

1. In the first foryou must indicate which is the current record (with its idMenu)
2. In the forinternal, you must process only those that match that current id (right now you process them all), that isif (actual == i.getmenu().getIdMenu())
3. After you place all the submenus for a menu, mark them in some way so that in the next iteration they are not taken into account and therefore do not duplicate your menu component.

Your inconvenience is to identify who has already been processed so that they are not processed again. I propose the following:

In your classes SubMenuand Menucreate an attribute boolean procesado(with its getterand setter), the processed attribute of SubMenuwill be given a value trueinside the forinner and the processed attribute of Menuwill be given a value truewhen leaving the forinner.

For each iteration of the formain one, you will only enter to process the record if it has the attribute procesadowith value false. Modify your method establecerPermisos()like so:

//Marco con /**/ las líneas que debes agregar

public void establecerPermisos() {
    for(SubMenu m : lista) {

/**/    if(!m.isProcessed()) { //colocar este atributo en el Bean SubMenu
/**/    int actual = m.getMenu().getIdMenu();

        if(m.getMenu().getTipo().equals("S")) {
            DefaultSubMenu firstSubMenu=new DefaultSubMenu(m.getMenu().getNomMenu());

            for(SubMenu i:lista) {
/**/            if(actual == i.getMenu().getIdMenu() && !i.isProcessed()) {
                    Menu menu= i.getMenu();

                    if(menu!=null) {
                        if(menu.getIdMenu()==m.getIdsubmenu()) {
                            DefaultMenuItem item=new DefaultMenuItem(i.getNombresubmenu());
                            firstSubMenu.addElement(item);
/**/                i.setProcessed(true);
                        }
                    }
/**/            }
            }
            model.addElement(firstSubMenu);
/**/        m.getMenu().setProcessed(true); //colocar este atributo en el Bean Menu
        } else {
             if(m.getIdsubmenu() == 0) {
                 DefaultMenuItem item = new DefaultMenuItem(m.getNombresubmenu());
                 model.addElement(item);
             }
        }       
/**/ }
    }
}

Try this approach for your rendering and let us know. Cheers,

The response after debugging. You had to initialize the menu and submenu on each iteration of the loop while:

while(rs.next()){  

    Menu menu = new Menu();
    SubMenu submenu = new SubMenu();

    menu.setIdMenu(rs.getInt("m.idMenu"));             
    menu.setCodMenu(rs.getString("m.codMenu"));    
    menu.setNomMenu(rs.getString("nomMenu"));
    menu.setLink(rs.getString("m.link"));
    menu.setTipo(rs.getString("m.tipo"));
    menu.setEstadomenu(rs.getString("m.estadoMenu"));
    submenu.setIdsubmenu(rs.getInt("s.idSubMenu"));
    submenu.setItemsubmenu(rs.getString("s.itemSubMenu"));
    submenu.setNombresubmenu(rs.getString("s.nombreSubMenu"));
    submenu.setLinksubmenu(rs.getString("s.linkSubMenu"));
    submenu.setEstadosubmenu(rs.getString("s.estadoSubMenu"));
    submenu.setTipo(rs.getString("s.tipo"));
    menu.setIdMenu(rs.getInt("s.idMenu"));
    submenu.setMenu(menu);
    lista.add(submenu);  
    //lista3.add(menu);
} 

But at the moment of executing the menus are duplicated with their corresponding submenu, if someone of you can give me ideas in the solution, thank you very much.

Well I hope someone helps me

well in my opinion the problem is

for(SubMenu m:list){

         if(m.getMenu().getTipo().equals("S")){          
            DefaultSubMenu firstSubMenu=new DefaultSubMenu(m.getMenu().getNomMenu());

I am going to add an if to control the repeated menus but I don't know how I can control it. I have made comparisons with codigodesubmenu vs codmenu but it does not work. How do I compare the menu codes and if it is repeated, show it only once.

I hope someone can help me with another approach. Cheers

I leave the image of the query the database is in MYSQL you will notice that they are two related tables