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k1k4ss0
Asked: 2020-01-06 11:56:57 +0800 CST 2020-01-06 11:56:57 +0800 CST

string.search(".") always returns 0

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Well, when I execute code in javascript and I have a string like for example:

 var variable="esto es una . cadena con punto".search(".");

Well, it gives 0, I have searched and apparently search() returns 0 when it does not have parameters or they are not initialized, something that I do not understand because I am explicitly passing the string that it has to search for...

javascript

2 Answers

  1. Best Answer

    This is because the search method does not receive a string, but a regular expression or a string to make a regular expression, i.e. your code is equivalent to

    var variable = "esto es una . cadena con punto".search(".");
console.log(variable);
var variable1 = "esto es una . cadena con punto".search(new RegExp("."));
console.log(variable1);
var variable2 = "esto es una . cadena con punto".search(new RegExp(/./));
console.log(variable2);
var variable3 = "esto es una . cadena con punto".search(/./);
console.log(variable3);

    the .in a regular expression means any character, so you can correct your code by escaping the dot so it doesn't take it as any character:

    var variable = "esto es una . cadena con punto".search(new RegExp(/\./));
console.log(variable);
var variable1 = "esto es una . cadena con punto".search(new RegExp("\\."));
console.log(variable1);
var variable2 = "esto es una . cadena con punto".search("\\.");
console.log(variable2);
var variable3 = "esto es una . cadena con punto".search(/\./);
console.log(variable3);

    • 2

  2. I have found a different way to find the index or position of the "." character, you can use:

       string.indexOf(".");

    It will return your position.

    • 0