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Wilmilcard
Asked: 2020-10-31 07:31:34 +0800 CST 2020-10-31 07:31:34 +0800 CST

Can you Deserialize and map a modelless Json in C#?

  • 772

What happens is that I have a request, I have a Json but I need to capture the value, but I have to do it without using a Model, I have seen examples but they all handle models.

is it possible to deserialize without a model?

At the moment I am doing it like this:

Step 1:

I create the Json from PostMan

{
   "CAMPO_EN_LA_TABLA": "valor que quiero capturar"
}

Step 2:

Create a Private model in the class, so you can serialize:

private class Parametros
{
    [Key]
    public int Empid { get; set; }

    public string Codigo { get; set; }

    [Column(TypeName = "sql_variant")]
    public object Valor { get; set; }
}

Step 3:

I deserialize it like this in a Dictionary:

var listParametros = JsonConvert.DeserializeObject<Parametros>(valor.ToString());

Step 4:

And the last thing is to capture the value and save it in some parameter:

object ValorCapturado = listParametros.Valor;
Console.WriteLine("Este es el valor impreso: " + listParametros.Valor);

As you can see, I know how to deserialize, but in the requirements they ask me to do it without the Model, but I don't know how to map it like that

c#

3 Answers

  1. Best Answer

    If you need to deserialize generically, you can use theJObject

    Parsing JSON Object using JObject.Parse

    string json = @"{
  CPU: 'Intel',
  Drives: [
    'DVD read/writer',
    '500 gigabyte hard drive'
  ]
}";

JObject o = JObject.Parse(json);

    can be deserialized without an object

    Using JSON.NET for dynamic JSON parsing

    parse the title "Importing JSON with JObject.Parse() and JArray.Parse()" but it basically defines

    var jsonString = @"{""Name"":""Rick"",""Company"":""West Wind"",
                    ""Entered"":""2012-03-16T00:03:33.245-10:00""}";

dynamic json = JValue.Parse(jsonString);

string name = json.Name;
string company = json.Company;
DateTime entered = json.Entered;

    al usar dynamic no tendrias problema en deserializar el json sin una clase

    If you use the JObject you can access the nodes

    Parse JSON object in C# with different value types

    string sampleJson = "{\"results\":[" +
    "{\"employeename\":\"name1\",\"employeesupervisor\":\"supervisor1\"}," +
    "{\"employeename\":\"name2\",\"employeesupervisor\":\"supervisor1\"}," +
    "{\"employeename\":\"name3\",\"employeesupervisor\":[\"supervisor1\",\"supervisor2\"]}" +
    "]}";

// Parse JSON into dynamic object, convenient!
JObject results = JObject.Parse(sampleJson);

// Process each employee
foreach (var result in results["results"])
{
    // this can be a string or null
    string employeeName = (string)result["employeename"];

  //resto codigo

    In short you could use the JObject or dynamic to deserialize without a class to map the json to

    • 2

  2. Try doing the following:

    dynamic d = JObject.Parse("{number:1000, str:'string', array: [1,2,3,4,5,6]}");

Console.WriteLine(d.number);
Console.WriteLine(d.str);
Console.WriteLine(d.array.Count);

    we get a dynamic object without using a model. I hope it helps you, Greetings!

    Documentation

    • 0

  3. One way to do what you're looking for is to use the dynamic type and JsonConvert.DeserializeAnonymousType Method (String, T)

    using Newtonsoft.Json;
//Creo un string con un JSON de ejemplo
string JsonDeEjemplo = "[{'CAMPO_EN_LA_TABLA': 'valor que quiero capturar'}, {'CAMPO_EN_LA_TABLA': 'segundo valor que quiero capturar'}, {'CAMPO_EN_LA_TABLA': 'tercer valor que quiero capturar'}]";            
//Uso DeserializeAnonymouseType para obtener un List<dynamic> con el contenido deserializado
var ListaDinamica = JsonConvert.DeserializeAnonymousType<List<dynamic>>(JsonDeEjemplo,null);
//Por cada variable dynamic en ListaDinamica..
foreach(var Dyn in ListaDinamica)
{
    //Muestro la propiedad CAMPO_EN_LA_TABLA
    Console.WriteLine(Dyn.CAMPO_EN_LA_TABLA);
}

    I leave you a dotnetfiddle of the working example

    • 0