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Megane
Asked: 2020-10-05 06:30:48 +0800 CST 2020-10-05 06:30:48 +0800 CST

How to insert the "%" symbol in a Bat file?

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I am creating a program in DOS code with extension ".bat"but I have the small problem that I want to show a percentage and for this I need to print the symbol on the screen "%".

I have to add that I already tried with "%", '%' and % but none of those three ways worked for me, I would appreciate the help.

batch

2 Answers

  1. It's a bit strange but you need to use %%to escape only that sign. For others see this list.

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  2. Best Answer

    If I'm not wrong, in DOS code you could print any symbol with a double percentage, that is, %así%.

    Since the double percentage calls a variable, but if the variable is empty, it prints its name, so if we have a variable called "X" and its content is "3", when we say it echo %X%will print "3" but if this variable is empty or not defined, then it will print "X".

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