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Katz
Asked: 2020-07-26 20:33:44 +0800 CST 2020-07-26 20:33:44 +0800 CST

How to format a string at a fixed position?

  • 772

My program tries to look for web page links And when the page is valid the application writes [+] Found [+] and if the link is not valid it writes [+] Error [+] but each link does not have the same length. Here is an example of how the app looks when I run it foobar.com/test [+] Found [+] foobar.com/test21 [+] Error [+] foobar.com/test333 [+] Error [+]

As you can see the position of the message moves because the link is longer. I want the message from Foundo Errorto appear in the same vertical row like this:

foobar.com/test [+] Found [+] foobar.com/test21 [+] Error [+] foobar.com/test333 [+] Error [+]

But not so close to the link because there may be an error that would be if a link is longer than the length between the link and the message Erroror Found Here is my code

for i in array:
    try:
        adminpanel = urllib2.urlopen(website+i)
        checkurl = adminpanel.code
        if checkurl == 200:
            print Fore.GREEN+ website+i," ""                                              " +"[+] Found [+] "
            continue
    except urllib2.URLError, checkurl:
        if checkurl == 404:
            print website+i," ""              Not Found :/"
        else:
            print Fore.RED+ website+i," ""                                              " +"[+] Error [+] " + Style.RESET_ALL
python

1 Answers

  1. Best Answer

    If you know all the links in advance, which it seems you do, you can do the following:

    # Imaginando que los enlaces sin el prefijo están en 'array'
array = ['test', 
         'longer', 
         'longest'] # este es el más largo

website = 'footest.com/'

length = max(map(len, enlaces)) + len(website)

for i in array:
    try:
        adminpanel = urllib2.urlopen(website+i)
        checkurl = adminpanel.code
        lenght_url = len(website + i)
        if checkurl == 200:
            print(Fore.GREEN + website+i, 
                  " " * (lenght - length_url) + "  [+] Found [+]")
            continue
    except urllib2.URLError, checkurl:
        lenght_url = len(website + i)
        if checkurl == 404:
            print(website + i," ""              Not Found :/")
        else:
            print(Fore.RED + website + i,
                  " " * (lenght - length_url) + "  [+] Error [+] " + style.RESET_ALL)

    The above code should leave you two spaces at the end of the longest link and more spaces at the end of the other links.

    In the part of your code I add the desired number of spaces in each printusing the maximum length of a link and the length of the link in use in order to be able to enter the necessary number of spaces.

    [I haven't tested the code since I don't have a python2.7 installed on this PC]

    • 2