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Mari Cruz
Asked: 2020-05-14 05:51:06 +0800 CST 2020-05-14 05:51:06 +0800 CST

What is wrong with my code to overcome the else if condition?

  • 772

I have this challenge that I cannot overcome. I am only missing one of the following three conditions: orderMyLogic(4) should return "Less than 5" orderMyLogic(6) should return "Less than 10" orderMyLogic(11) should return "Greater than or equal to 10" I have Tried countless changes and I'm always missing one of the conditions. With this code, I am getting past: orderMyLogic(6) should return "Less than 10" orderMyLogic(11) should return "Greater than or equal to 10" . But this fails me: orderMyLogic(4) should return "Less than 5" I show my code so you can see what I'm doing wrong. Thanks.

function orderMyLogic(val) {
  if (val < 10 ) {
    return "Less than 10";
  } else if (val < 5) {
    return "Less than 5";
  } else {
    return "Greater than or equal to 10";
  }
}

// Change this value to test
orderMyLogic(4);

javascript

1 Answers

  1. Best Answer

    I will tell you the following, as well as this, your code does not work because the number 4 also fits in the first condition, that is why it does not go to your second else if; To get the desired value you must do the following:

    function orderMyLogic(val) {
  if (val < 10 && val > 5) {
    return "Less than 10";
  } else if (val < 5) {
    return "Less than 5";
  } else {
    return "Greater than or equal to 10";
  }
}

// Change this value to test
console.log(orderMyLogic(4))

    As you can see, to control the behavior in the if I add a logical operator called AND that asks for the following: the value must be less than 10 and greater than 5, so when you write the value 4 it does not enter that if, but is passed to the if second to the else if and in this way you manage to control the behavior that you are expecting

    • 2