How to generate random decimal numbers in Java within range?

randshould have a method nextDouble. This method accepts no arguments as it generates a number between 0.0 and 1.0. To adjust that number to your range you can use code similar to this:

double randomNum = min + ( max - min ) * rand.nextDouble();

This is a very useful method, very important to usenextDouble()

public static double getRandom(Double valorMinimo, Double valorMaximo) {
        Random rand = new Random();
        return  valorMinimo + ( valorMaximo - valorMinimo ) * rand.nextDouble();
    }

nextDouble() method that is used to get the next pseudo-random, uniformly distributed value between 0.0 and 1.0 from the sequence of this number from the random generator.

As an example:

Using the method described above, write 100 random numbers between the values ​​1.1 and 2.5:

System.out.println(String.valueOf(getRandom(1.1, 2.5)));

see demo here!

could you use this

(Math.random()*20)+1;

Which would create a random between 1 and 19 with decimals.

19 = 20 - 1 // Max - Min

You can generate a random in which the minimum value is ( min + 100) and then divide the number obtained by 100.0. In this way you would get a number with two decimal places:

double randomNum = rand.nextInt((max - min) + 1) + min + 100 / 100.0

You can use this code , just be careful that this code will never give you the value of max:

function randomInRange(min, max) {
  return Math.random() * (max-min) + min;
}

Use the class Math, though surely you could also use the nextDoubleclass function Random.

Random r = new Random();

double randomValue = rangeMin + (rangeMax - rangeMin) * r.nextDouble();