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Asked: 2020-11-16 08:16:02 +0800 CST 2020-11-16 08:16:02 +0800 CST

How to sort an array made up of objects using .sort()

  • 772

I have a file that contains the object I want to manipulate. I think two for example. But when in the showArrayOrdenado() function I apply the sort() to order it, since it is about objects and not literals. don't order me My idea is that they are ordered by the name parameter of each object that makes up the array. It's possible?

function Sandskill(nom, edad, especialidad, comp) {
  this.nombre = nom;
  this.edad = edad;
  if (especialidad == 1 || especialidad == 2 || especialidad == 3) {
    if (especialidad == 1)
      this.especialidad = "sistemas";
    if (especialidad == 2)
      this.especialidad = "web";
    if (especialidad == 3)
      this.especialidad = "multiplataforma";
  } else {
    this.especialidad = null;
  }
  this.comp = comp;

  //GETTER
  this.getNom = function() {
    return this.nombre;
  }
  this.getEdad = function() {
    return this.edad;
  }
  this.getEspecialidad = function() {
    return this.especialidad;
  }
  this.getComp = function() {
    return this.comp;
  }
}

var s1 = new Sandskill("Pepe", "22", "1");
var s2 = new Sandskill("Juan", "22", "2", s1);

function mostrarArrayOrdenado() {
  sandskillArray.sort();
  for (i = 0; i < sandskillArray.length; i++) {
    alert(sandskillArray[i].getNom() + " * " + sandskillArray[i].getEdad() + " * " + sandskillArray[i].getEspecialidad() + " * ")
  }
}

javascript

1 Answers

  1. Best Answer

    The sort() method, as you can see on the MDN website , can receive a comparator function as a parameter that has the following form:

    function compare(a, b) {
  if (a es menor que b según criterio de ordenamiento) {
    return -1;
  }
  if (a es mayor que b según criterio de ordenamiento) {
    return 1;
  }
  // a debe ser igual b
  return 0;
}

    In your case, it could be something like:

    sandskillArray.sort(function (o1,o2) {
  if (o1.nombre > o2.nombre) { //comparación lexicogŕafica
    return 1;
  } else if (o1.nombre < o2.nombre) {
    return -1;
  } 
  return 0;
});
    • 4